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Please, I Need Solution To This Mathematics Question (263 Views)
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sirAmeh(m): 3:40pm On Jun 01 |
I need help with this Mathematics question
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muyico(m): 3:57pm On Jun 01 |
Let me help u ask Google brb!
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CodeTemplarr: 4:09pm On Jun 01 |
Forgotten the formula for volume of a cone. Treat each end as a cone and the middle as a cylinder.
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rhemahills(m): 4:44pm On Jun 01 |
To find the volume of the pencil, which consists of a central cylinder and two cones (one at each end), we use the following data from your diagram: Length of the cylindrical part: 16 cm Radius of the pencil: 1 cm Length of each cone: 1.2 cm Use π = 22 7 π= 7 22 Step 1: Volume of the Cylinder Volume cylinder = π r 2 h = 22 7 × ( 1 ) 2 × 16 = 22 7 × 16 = 50.29 cm 3 Volume cylinder =πr 2 h= 7 22 ×(1) 2 ×16= 7 22 ×16=50.29 cm 3 Step 2: Volume of One Cone Volume cone = 1 3 π r 2 h = 1 3 × 22 7 × ( 1 ) 2 × 1.2 = 1 3 × 22 7 × 1.2 = 1.257 cm 3 Volume cone = 3 1 πr 2 h= 3 1 × 7 22 ×(1) 2 ×1.2= 3 1 × 7 22 ×1.2=1.257 cm 3 But for two cones: Total volume of cones = 2 × 1.257 = 2.514 cm 3 Total volume of cones=2×1.257=2.514 cm 3 Step 3: Total Volume Total volume = Volume cylinder + Total volume of cones Total volume=Volume cylinder +Total volume of cones = 50.29 + 2.514 = 52.8 cm 3 =50.29+2.514=52.8 cm 3 Final Answer: The volume of the pencil is 52.8 cm³. 2 Likes 1 Share |
Firebox123(m): 5:13pm On Jun 01 |
![]() rhemahills: |
CJStarz: 7:21pm On Jun 01 |
rhemahills:Respects |
Inspirer1: 8:32pm On Jun 01 |
sirAmeh:From the diagram, the pencil has 2 Cones and one Cylinder, diameter = 1 cm, therefore radius = 0.5 cm, π = 22/7 Volume of a Cone = 1/3 πr²h Where r = 0.5 cm, height h = 1.2 cm Vol. Cone = 1/3 * 22/7 * 0.5 * 0.5 * 1.2 cm = 0.314 cm³ Since there are 2 Cones, Volume of 2 Cones = 2 X 0.314 = 0.628 cm³ = 0.63 cm³ Volume of Cylinder = π r²h where r = 0.5 cm, h = 16 cm Volume of Cylimber= πr²h Volume of Cylinder = 22/7 X 0.5 X 0.5 X 16 = 88/7 = 12:57cm³ Total Volume of pencil = volume of cones + volume of Cylinder = 0.63 cm³ + 12.57cm³ = 13.2cm³ Cc: sirAmeh 1 Like |
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